Function.name

A Function object's read-only name property indicates the function's name as specified when it was created, or it may be either anonymous or '' (an empty string) for functions created anonymously.

Source code such as:

function Foo() {};
let foo = new Foo();

if (foo.constructor.name === 'Foo') {
  console.log("'foo' is an instance of 'Foo'");
} else {
  console.log('Oops!');
}

may be compressed to:

function a() {};
let b = new a();
if (b.constructor.name === 'Foo') {
  console.log("'foo' is an instance of 'Foo'");
} else {
  console.log('Oops!');
}

In the uncompressed version, the program runs into the truthy-branch and logs "'foo' is an instance of 'Foo'". Whereas, in the compressed version it behaves differently, and runs into the else-branch. If you rely on Function.name, like in the example above, make sure your build pipeline doesn't change function names, or don't assume a function to have a particular name.

The name property returns the name of a function statement.

function doSomething() {}
doSomething.name; // "doSomething"

Functions created with the syntax new Function(...) or just Function(...) create Function objects and their name is "anonymous".

(new Function).name; // "anonymous"

Anonymous function expressions that were created using the keyword function or arrow functions would have "" (an empty string) as their name.

(function() {}).name; // ""
(() => {}).name; // ""

Variables and methods can infer the name of an anonymous function from its syntactic position (new in ECMAScript 2015).

let f = function() {};
let object = {
  someMethod: function() {}
};

console.log(f.name); // "f"
console.log(object.someMethod.name); // "someMethod"

You can define a function with a name in a function expression:

let object = {
  someMethod: function object_someMethod() {}
};
console.log(object.someMethod.name); // logs "object_someMethod"

try { object_someMethod } catch(e) { console.log(e); }
// ReferenceError: object_someMethod is not defined

The name property is read-only and cannot be changed by the assignment operator:

 let object = {
  // anonymous
  someMethod: function() {}
};

object.someMethod.name = 'otherMethod';
console.log(object.someMethod.name); // someMethod

To change it, use Object.defineProperty().

Function.bind() produces a function whose name is "bound " plus the function name.

function foo() {};
foo.bind({}).name; // "bound foo"

When using get and set accessor properties, "get" or "set" will appear in the function name.

let o = {
  get foo(){},
  set foo(x){}
};

var descriptor = Object.getOwnPropertyDescriptor(o, "foo");
descriptor.get.name; // "get foo"
descriptor.set.name; // "set foo";

You can use obj.constructor.name to check the "class" of an object (but be sure to read the warnings below):

function Foo() {}  // ES2015 Syntax: class Foo {}

var fooInstance = new Foo();
console.log(fooInstance.constructor.name); // logs "Foo"

Therefore we can't obtain the class name for virtually any class with a static method property name():

class Foo {
  constructor() {}
  static name() {}
}

With a static name() method Foo.name no longer holds the actual class name but a reference to the name() function object. Above class definition in ES2015 syntax will behave in Chrome or Firefox similar to the following snippet in ES5 syntax:

function Foo() {}
Object.defineProperty(Foo, 'name', { writable: true });
Foo.name = function() {};

Trying to obtain the class of fooInstance via fooInstance.constructor.name won't give us the class name at all but a reference to the static class method. Example:

let fooInstance = new Foo();
console.log(fooInstance.constructor.name); // logs function name()

You may also see from the ES5 syntax example that in Chrome or Firefox our static definition of Foo.name becomes writable. The built-in definition in the absence of a custom static definition is read-only:

Foo.name = 'Hello';
console.log(Foo.name); // logs "Hello" if class Foo has a static name() property but "Foo" if not.

Therefore you may not rely on the built-in Function.name property to always hold a class's name.

If a Symbol is used a function name and the symbol has a description, the method's name is the description in square brackets.

let sym1 = Symbol("foo");
let sym2 = Symbol();
let o = {
  [sym1]: function(){},
  [sym2]: function(){}
};

o[sym1].name; // "[foo]"
o[sym2].name; // ""

• A polyfill for functions .name property is available in core-js
• Function