AudioBuffer.copyFromChannel()
The
copyFromChannel() method of the
AudioBuffer interface copies the audio sample data from the specified
channel of the AudioBuffer to a specified
Float32Array.
Syntax
myArrayBuffer.copyFromChannel(destination, channelNumber, startInChannel);
Parameters
destination-
A
Float32Arrayto copy the channel's samples to. channelNumber-
The channel number of the current
AudioBufferto copy the channel data from. startInChannelOptional-
An optional offset into the source channel's buffer from which to begin copying samples. If not specified, a value of 0 (the beginning of the buffer) is assumed by default.
Return value
undefined.
Exceptions
indexSizeError-
One of the input parameters has a value that is outside the accepted range:
-
The value of
channelNumberspecifies a channel number which doesn't exist (that is, it's greater than or equal to the value ofnumberOfChannelson the channel). -
The value of
startInChannelis outside the current range of samples that already exist in the source buffer; that is, it's greater than its currentlength.
-
The value of
Example
This example creates a new audio buffer, then copies the samples from another channel into it.
var myArrayBuffer = audioCtx.createBuffer(2, frameCount, audioCtx.sampleRate);
var anotherArray = new Float32Array(length);
myArrayBuffer.copyFromChannel(anotherArray, 1, 0);
Specifications
| Specification |
|---|
| Web Audio API # dom-audiobuffer-copyfromchannel |
Browser compatibility
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